The Rotation - Energy Value

The Schroedinger equation for two particles moving in the potential which depends only on the distance r between the particles is as follows
 

(−h²/Δ + V(r)) y  =  E y

(1)

where µ is the reduced mass of both particles A and B, mA and mB: µ = mAmB/(mA+mB). Now we would like to find possible solutions for y and corresponding energy E. Since we have the sphere-symmetrical system here then we will use the Polar coordinates for solving the above-mentioned equation.
 

 x  =  r sinJcosj
 y  =  r sinJsinj
z  =  r cosJ

We must transform only Δ into polar coordinate beacause the potential V(r) has been already given in polar coordinate system:

Δ  =  ∂²/∂x² + ∂²/∂y² + ∂²/∂z²

1/ /∂r(/∂r) 1/h²

where the operator  (J,j) is the kinetic moment operator taken to the square of polar coordinates and depends only on angles but not on distance r.

When we have the diatomic molecule A-B which rotates around the common center, the connection length would change due to centrifugal forces. In our simplified treatment, we will assume the atoms to have constant distance, as if the atoms were connected by solid rod. It's also referred to as rigid rotator. The radial coordinate r is constant, the corresponding derivatives vanish and V(r) can be equal to 0. And one obtain ODE after that:

1/2µr² Y  =  E Y

where we write down the wavefunction y instead of Y  that can depend only on angles J,j. If we also introduce the moment of inertia I = µr²  we will finally obtain:

Y  =  2I·E Y

Therefore the ODE solution for corresponding angles corresponds to the definition of the eigenfunction of the squared kinetic moment operator. That's why the quantity 2I·E represents the eigenvalues. What values are possible? The mathematical treatment of kinetic moment eigenvalues shows that only values l(l+1)h² are possible moreover l can take only integer values l = 0,1,2,3,...during rotation:
 

Y  =  h² l(l+1) Y
(2)

One can write down for the rotational energy:
 

E  =  h²/2Il(l+1)  E  =  B l(l+1)  l = 0,1,2,...

where the quantity h²/2I is shortened by B. In general B is in wavenumbers [cm-1] so that: B [cm-1] = h²/2Ihc = h/8π²cI where c is the speed of light.